Question

For ax2 + bx + c = 0, which of the following statement is wrong? *

1 point

A) If b2 – 4ac is a perfect square, the roots are rational.

B) If b2 = 4ac, the roots are real and equal.

C) If b2 – 4ac is negative, no real roots exist.

D) If b2 = 4ac , the roots are real and unequal.

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Answer 1

Answer: D )

Step-by-step explanation:

as we know the nature of roots is determined by it's discriminant

i.e D = b²-4ac

as b²= 4ac : D = 0

so when we take the sqare root of zero we get it as zero only

so the zeros of the polynomial will be -b/2a

so we can conclude that is the d= 0 the zeros of the polynomial are real and equal