Question

for be which value of K will Pair of equations KX+3y= K-3 12x +ky=k have no solution ​

Answer 1

Answer:

-6

Step-by-step explanation:

for pair of equations to have no solution,

a1/a2 = b1/b2 not = c1/c2

k/12 = 3/k not = (k-3)/k

k² = 36

k = +6 or -6

3/k not = (k-3)/k

if k = +6, above condition not satisfied

if k = -6, above condition is satisfied

So k = -6

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