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Without actually calculating the cubes find the value of the above!!
Plz Answer
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Answered by
43
Hey !!! ^_^
Here is your answer
⬇️⬇️⬇️⬇️⬇️
1️⃣ (25)³ + (-12)³ + (-13)³
x = 25 , y = -12 and z = - 13
As we know ,
x + y + z = 0
x³ + y³ + z³ = 3xyz
(25)³ + (-12)³ + (-13)³ = 3(25)(-12)(-13)
11,700
2️⃣ (-32)³ + (20)³ + (12)³
x = -32 , y = 20 and z = 12
x + y + z = 0
x³ + y³ + z³ = 3xyz
3(-32)(20)(12)
- 7680
`_________________________
I HOPE IT WILL HELP You ☺️✌️
Here is your answer
⬇️⬇️⬇️⬇️⬇️
1️⃣ (25)³ + (-12)³ + (-13)³
x = 25 , y = -12 and z = - 13
As we know ,
x + y + z = 0
x³ + y³ + z³ = 3xyz
(25)³ + (-12)³ + (-13)³ = 3(25)(-12)(-13)
11,700
2️⃣ (-32)³ + (20)³ + (12)³
x = -32 , y = 20 and z = 12
x + y + z = 0
x³ + y³ + z³ = 3xyz
3(-32)(20)(12)
- 7680
`_________________________
I HOPE IT WILL HELP You ☺️✌️
arinsingh14:
I am bro
Answered by
28
for i) (25)^3+(-12)^3+(-13)^3
let a=25, b=-12, c=-13
a+b+c=25+(-12)+(-13)
=25-25
=0
if, a+b+c=0
Then, a^3+b^3+c^3=3abc
25^3+(-12)^3+(-13)^3=3×25×(-12)×(-13)
=11,700
do another question same like this.
Mark it as a brainliest
let a=25, b=-12, c=-13
a+b+c=25+(-12)+(-13)
=25-25
=0
if, a+b+c=0
Then, a^3+b^3+c^3=3abc
25^3+(-12)^3+(-13)^3=3×25×(-12)×(-13)
=11,700
do another question same like this.
Mark it as a brainliest
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