Math, asked by Blesston, 1 year ago

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Without actually calculating the cubes find the value of the above!!

Plz Answer

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Answered by Anonymous
43
Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️


1️⃣ (25)³ + (-12)³ + (-13)³


x = 25 , y = -12 and z = - 13


As we know ,

x + y + z = 0

x³ + y³ + z³ = 3xyz

(25)³ + (-12)³ + (-13)³ = 3(25)(-12)(-13)

11,700


2️⃣ (-32)³ + (20)³ + (12)³


x = -32 , y = 20 and z = 12


x + y + z = 0


x³ + y³ + z³ = 3xyz

3(-32)(20)(12)

- 7680


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I HOPE IT WILL HELP You ☺️✌️

thank \: you


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Anonymous: nope
Answered by arinsingh14
28
for i) (25)^3+(-12)^3+(-13)^3
let a=25, b=-12, c=-13
a+b+c=25+(-12)+(-13)
=25-25
=0
if, a+b+c=0
Then, a^3+b^3+c^3=3abc
25^3+(-12)^3+(-13)^3=3×25×(-12)×(-13)
=11,700

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