Question

for circle with Centre o two tangets P A and PB from an angle of 80 degree from an external point P find m angle POA​

Answer 1

Step-by-step explanation:Answer:

GIVE: ∠APB=80°

As we know that sum of ∠APB+∠AOB=180°

(Using Property)

∠AOB=100°

Δ AOP ≃ ΔBOP by SSS congruency criteria.

AO=BO (Radius of circle)

PO=PO (common side of triangle)

AP=BP (tangents form an external point)

∠AOP=∠BOP (CPCT )

∠POA+∠POB=∠AOB=100°

∠POA=50°

Answer 2

Refer to the attachment.

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