for college expenses, a student took out a loan at 4.00% and a semester later took out a second loan at 3.00%. the total annual interest for the two loans was $245. if the second loan had been for twice as much, the annual interest would have been $290. how much was each loan?
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290-98-56-45-632-15-78+659+
sweetysiri92:
can you give the detailed explanation
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0.04x +0.5*0.03y =245
0r, 0.04x +0.015 y =245
0.04x + 0.015 *2y = 290
0.04x+ 0.03y =290
subtracting first equation from second
0.015y=45
y= 3000
x=(290-0.03*3000)/0.04
=(290-90)/0.04
=200/0.04
=5000
answer $ 5000 and $ 3000 respectively
0r, 0.04x +0.015 y =245
0.04x + 0.015 *2y = 290
0.04x+ 0.03y =290
subtracting first equation from second
0.015y=45
y= 3000
x=(290-0.03*3000)/0.04
=(290-90)/0.04
=200/0.04
=5000
answer $ 5000 and $ 3000 respectively
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