Question

For combustion of 1 mole of benzene at 25 °C,
the heat of reaction at constant pressure is
-780.9 kcal. What will be the heat of reaction at constant volume?
C6H6(l)+7/2.02(g)
→6CO2.(g) + 3H20(l)
(a) -781.8 kcal
(c) + 781.8 kcal
(b) -780.0 kcal
(d) + 780.0 kcal
​

Answer 1

Answer:

options 3bjshgshsjsjajajkakakakakkalaksks