for completing a work a second man needs 5 days more than a first man claimed there together did the work in 6 days find the number of days required by the first man alone to complete the work.
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Answer:
Thus I man complete the work in 10 days
Step-by-step explanation:
let I can complete the work in x days
One day's work of I =1/x
then II man needs=x+5 days
One day's work of II =1/(x+5)
One day's work I and II person
=1/x+1/(x+5)=(x+5+x)/(x(x+5) )
=(2x+5) /x(x+5)
Day' required to complete the work
=1/ ((2x+5) /x(x+5))=x(x+5)/(2x+5)
so x(x+5)/(2x+5)=6
x(x+5)=6*(2x+5)
x²+5x=12x+30
x²-7x-30=0
(x-10)(x+3)=0
x=10 or -3
x can not be -ve
Thus I man complete the work in 10 days
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