Question

for complex no z1=6+3i, z2=3-i
find (z1/z2)

Answer 1

Answer:

Z1/Z2 = 6+3i/3-i

rationalise

= (6+3i) × (3+i) / (3-i) × (3+i)

= 18+6i+9i+3i^2 / 9-i^2

(i^2 = -1)

= 18+15i-3 / 9+1

= 15+15i / 10

= 15(1+i) / 10

= 3(1+i) / 2

= 3/2 +3i/2