Question

for cu(oh)2 ksp=1.6×10^-19. what is the molar solubility​

Answer 1

Answer:

3.4×10∧−7M

Explanation:

For Cu(OH)2, the expression of solubility product is:

Ksp=[Cu²+][OH−]²=(s)(2s)²=4s³

Substitute Ksp=1.6×10∧−19 in the above expression:

1.6×10∧−19=4s³

s=3.4×10∧−7

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