Question

for current carrying solid conductor uniform current density and radius r​

Answer 1

Magnetic field at a distance r inside a conductor of radius R is given by ampere’s circuital law B × 2π r = μ0Jπr2 B = μ0Jr2 B = μ0rI2πR2

Ampere's law says that ∮B·dl = μ·I ,Here B.dl is equal to ∮B·dl Here, dl is 2π r And I = ∫J.da Finally, B × 2π a/2 = μ0 × ∫ 0a/2J0 ×