For d block elements the first ionization potential is of the order :
(a) Zn > Fe > Cu > Cr
(b) Sc = Ti < V = Cr
(c) Zn < Cu < Ni < Co
(d) V > Cr > Mn > Fe
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Answer:
(a) Zn > Fe > Cu > Cr is the correct answer. The first ionization energy of Zn is 906 KJ/mol, Fe is 759 KJ/mol, Cu is 745 KJ/mol and Cr is 650 KJ/mol.
Explanation:
What is first ionization potential:
- The first ionisation potential (IP1) is an atomic property that reflects the outermost electronic configuration.
- It is a measure of the energy necessary to remove one valence electron from a neutral atom.
- The ionization energy decreases from top to bottom in groups, and increases from left to right across a period.
Electronic configurations of:
- Zn -3d¹⁰ 4s²
- Fe - 3d² 4s2
- Cu - 3d¹⁰ 4s¹
- Cr - 3d⁵ 4s¹
From the electronic configuration we can understand the stability of those particles.
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