for decolorising 1 mole of kmno4, the moles of h202 required is a)1/2 b)3/2 c5/2 d)7/2
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3H2O2 + 2KMnO4 → 3O2 + 2MnO2 + 2KOH + 2H2O
2 mole kmno4 needs 3 moles of h2o2
therfore 1 mole of kmo4 need 1.5 moles of h2o2
(by unitary method
hope it helps you
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2KMnO4 + 3H2O2 → 2MnO2 + 2KOH + 2H2O + 3O2 For 2 mole of KMnO4 = 3 moles of H2O2 required. So for 1 mole = 3/2 moles = 1.5 ...
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