Math, asked by simrandhillon5736, 8 months ago

For disjoint set A and B n(A)=3,n(B)=5, then n(A?5nB)is

Answers

Answered by kirangusain84
3

Answer:

n(AUB)=n(A)+n(B)-n(A intersection B). Set A and B are disjoint sets therefore. n( A intersection B) =0. Then n(AUB= ...

13 votes

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1 vote

Since A and B are disjoint sets it is obvious that no element of A is repeated in B. n(A) ... More

2 votes

n(A union B) = n(A )+n(B ) - n(A intersection B) (This rule is becomes obvious with a Venn ... More

2 votes

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4 votes

By definition of disjoint set we mean that there won’t be any common elements in both the ... More

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Answered by NirmalPandya
0

Correct question: For two disjoint sets A and B, n(A)=3, n(B)=5, then n(A∪B)=?

Answer:

For the two disjoint sets A and B, n(A∪B)=8.

Given,

Two disjoint sets A and B have cardinalities 3 and 5 respectively.

To Find,

The cardinality of the set A∪B.

Solution,

The method of finding the cardinality of set A∪B is as follows.

We know that n(A∪B)=n(A)+n(B)-n(A∩B).

According to the question, A and B are two disjoint sets.

So n(A∩B) = 0.

Also, n(A)=3 and n(B)=5.

Then, n(A∪B)=n(A)+n(B)-n(A∩B) = 3+5-0 = 8.

Hence, for the two disjoint sets A and B, n(A∪B)= 8.

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