Question

For each integer n> 1, let A(n) denote the sum of the integers from 1 to n.
For example, A(100)=1+2+3+...+100=5,050. What is the value of A(200)?
A 10,100
B 15,050
© 15,150
D 20,100
€ 21,500​

Answer 1

Answer:

A(200)=A(100)+101+102+103...............+200A(200)=A(100)+101+102+103...............+200

=A(100)+(100+1)+(100+2)+(100+3)...............(100+100)=A(100)+(100+1)+(100+2)+(100+3)...............(100+100)

=A(100)+(1+2+................100)+100∗100=A(100)+(1+2+................100)+100∗100  

=5050+5050+10000=5050+5050+10000

=20100.

happy to help :)

Answer 2

Answer:

20100

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