Question

For each of the equations given below find the value of m if they have real and equal roots. i) (m – 3)x² − 4x + 1 = 0

Answer 1

Answer:

These equations are of the form ax²+bx+c=0 where a=m-3,b=-4,c=1

D=b²-4ac

For real roots D=0

Now,

b²-4ac=0

(-4)²-4×(m-3)×1=0

16-4m+12=0

28-4m=0

28=4m

[m=7]

Step-by-step explanation:

These equations are of the form ax²+bx+c=0 where a=m-3,b=-4,c=1

D=b²-4ac

For real roots D=0

Now,

b²-4ac=0

(-4)²-4×(m-3)×1=0

16-4m+12=0

28-4m=0

28=4m

[m=7]

(7-3)x²-4x+1=0

4x²-4x+1=0

4x²-(2+2)x+1=0

4x²-2x-2x+1=0

2x(2x-1)-1(2x-1)=0

(2x-1)(2x-1)=0

x=1/2,x=1/2

Answer 2

Here is the answer: ☝️☝️