Question

For each of the following, calculate the frequency, in hertz, and the period, in seconds:
(a) a pendulum swinging 20 times per minute

Answer 1

Answer:

$frequency = 0.33 \: hz \\ time \: period \: = 3sec$

Explanation:

A pendulum is swinging 20 times per minute

Hence,

$frequency = \frac{20}{1min} \\ frequency = \frac{20}{60sec} \\ frequency = \frac{1}{3} \\ frequency = 0.33 \: Hz$

$Time Period = \frac{1}{frequency} \\ Time Period = \frac{1}{ \frac{1}{3} } \\ Time Period = 3sec$

Answer 2

Given:

A pendulum swinging at 20 times per minute.

To Find:

The frequency of the pendulum in hertz and the time period of the pendulum in seconds.

Calculation:

- No of swings in 60 seconds (i.e., 1 min) = 20

⇒ Frequency = 20/60

⇒ Frequency = 1/3

⇒ Frequency = 0.33 Hz

- Time period = 1 / frequency

⇒ Time period = 1/0.33

⇒ Time period = 3 seconds

- So, the frequency of the pendulum is 0.33 hertz and the time period of the pendulum is 3 seconds.