For each of the following f find f'(a) for the given a; f(x)=x^3-4x, a=1
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Given
F(x) = x^3 - 4x
F'(x) = 3x^2 - 4
F'(a) = 3a^2 - 4
Since a=1
= 3(1)^2 -4 = -1
Therefore F'(a) = -1
F(x) = x^3 - 4x
F'(x) = 3x^2 - 4
F'(a) = 3a^2 - 4
Since a=1
= 3(1)^2 -4 = -1
Therefore F'(a) = -1
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