Question

for each of the following pair of numbers verify that LCM×HCF=Product of numbers. (1)21,28. (2)231and273. (3) 36,90​

Answer 1

Answer:

take out lcm nd hcf of the following number nd just put the value in following eqn i.e.lcm*hcf=a*b. and after solve both lhs and rhs will be equal. then write hence verify.

Step-by-step explanation:

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Answer 2

SOLUTION:-

(1) 21= 3×7

28 = 2×2×7

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LCM = 84

HCF = 7

LCM×HCF = 84×7= 588

product = 21×28 = 588

=> LCM×HCF = PRODUCT

(2) 231= 3×7×11

273= 3×7×13

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LCM = 3×7×11×13 = 3003

HCF = 3×7 = 21

LCM×HCF = 3003×21 = 63063

product = 231×373 = 63063

=> LCM × HCF = PRODUCT

(3) 36= 2×2×3×3

90 = 2×3×3×5

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LCM = 2×2×3×3×5 =180

HCF = 18

LCM×HCF = 180×18 = 3240

PRODUCT = 36×90 = 3240

=> LCM×HCF = PRODUCT

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