Question

For each pair of numbers, verify that their product =(HCF *LCM) (1) 87,145

Answer 1

HCF=29
LCM=435
87*145=12615
HCF X LCM=29*435=12615

Answer 2

Hloo dear...

According to the problem 

write given number 87 and 145 as product of prime.

87 = 3 × 29

145 = 5 ×29

HCF ( 87 , 145 ) = product of common prime factors = 29

LCM = maximum powers of prime factors =  3 × 5 ×29 = 435

Verification:
_________

i ) a × b = 87 × 145 = 12615

ii ) h × l = 29 × 435 = 12615

Therefore ,

                  a × b = h × l

I hope it is useful to you.