Question

For each value of l , the number of ms values are?
A. 2l
B. Nl
C. 2l+1
D. N-1

Answer 1

Answer:

c

Explanation:

ms = 2l + 1

ex : for l = 2 (d-orbital); ms= 5

i,e...-2, -1, 0, 1, 2

Answer 2

Answer:

c

Explanation:

ms=2I+1

ex: for I=2(d-orbital);ms=5

i.e...........-2,-1,0,1,2