Question

For each x ∈ R, let |x| be the greatest integer less than or equal to x. Then
lim ₓ→₀₊ [x([x] + |x|)sin [x]] ÷ |x| is equal to
(A) -sin1 (B) 0 (C) 1 (D) sin 1

Answer 1

Answer:

$\huge\boxed{\fcolorbox{black}{pink}{Hi mate!}}$

For each x ∈ R, let |x| be the greatest integer less than or equal to x. Then

lim ₓ→₀₊ [x([x] + |x|)sin [x]] ÷ |x| is equal to

(A) -sin1

(B) 0

(C) 1

(D) sin 1

Answer 2

Answer:

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For each x ∈ R, let |x| be the greatest integer less than or equal to x. Then

lim ₓ→₀₊ [x([x] + |x|)sin [x]] ÷ |x| is equal to

(A) -sin1 (B) 0 (C) 1 (D) sin 1✔