for ellipse 9x^2 +16y^2=576 find the eccentricity??
plzz plzz solve.!
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Answer-
9x^2 + 16y^2 = 576
We can write the given equation as-
x^2/16 + y^2/9 = 1
So a^2=16 and b^2=9
Since
b^2=a^2(e^2 - 1)
9 = 16(e^2-1)
e^2= 9/16+1
e^2= 25/16
e= +_ 5/4
9x^2 + 16y^2 = 576
We can write the given equation as-
x^2/16 + y^2/9 = 1
So a^2=16 and b^2=9
Since
b^2=a^2(e^2 - 1)
9 = 16(e^2-1)
e^2= 9/16+1
e^2= 25/16
e= +_ 5/4
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