Question

for equation ax²+bx+c=0 value are as a=√5,b=-1,c=-√5. find the value of didcriminant​

Answer 1

Answer:

Its Very simple my dear fellow let me show you :)

Solution:- a=√5,b=-1,c=√5

we know that, ∆ or discriminant=b^2-4ac

:. ∆=(-1)^2+4×√5×√5

:. ∆=1+4×5_______explaination:-√a×√a=a

:. ∆= 1+20

:. ∆= 21

hence the value of discriminat for equation ax^2+bx+c=0 is 21.