Question

) For equation for M2+ 4M + 4 = 0. Find value of discriminant.​

Answer 1

ax² + bx + c =0

b² - 4ac -------- (1)

a= 2 , b = 4 , c = 4

from 1st equation

4² - 4×2×4

= 8- 32

= 24

hope it will be help you

please mark me as branlist

Answer 2

$\huge{\color{lime}{\boxed{\mathtt{\orange{A}{\color{pink}{n}{\blue{s}{\red{w}{\green{e}{\color{yellow}{r}}}}}}}}}}$

$\huge\mathcal{\color{cyan}{Given}}$

$➠ \: {m}^{2}\:+\:4m\:+\:4\:=\:0$

__________________________________

$\On\: comparing \:the\:above\:given\: equation\:with\:$

${ax}^{2}\:+\:{bx}^{2}\:+\:c\:=\:0$

we get :

$a \:= \:1$

$b\:=\:4$

$c \:=\:4$

__________________________________

$∆\:=\:{b}^{2}\:-\:4ac$

$∆\:=\:{4}^{2}\:-\:4(1)(4)$

$∆\:=\:16\:-\:16$

$∆\:=\:0$

so the value of discriminant = 0 .