Question

*For equations y+2x=19 and 2x-3y=-3 find D.*

1️⃣ -8
2️⃣ -6
3️⃣ -4
4️⃣ 8​

Answer 1

Answer:

The value of D for the given simultaneous equations is - 8.

Option ( 1 )

Step-by-step-explanation:

The given simultaneous equations are

$\displaystyle{\sf\:y\:+\:2x\:=\:19\:\&\:2x\:-\:3y\:=\:-\:3}$

We have to find the value of determinant D.

Now,

$\displaystyle{\sf\:y\:+\:2x\:=\:19}$

$\displaystyle{\implies\sf\:2x\:+\:y\:=\:19\:\:\:-\:-\:(\:1\:)}$

$\displaystyle{\bullet\:\sf\:a_1\:=\:2}$

$\displaystyle{\bullet\:\sf\:b_1\:=\:1}$

$\displaystyle{\bullet\:\sf\:c_1\:=\:19}$

Now,

$\displaystyle{\sf\:2x\:-\:3y\:=\:-\:3\:\:\:-\:-\:(\:2\:)}$

$\displaystyle{\bullet\:\sf\:a_2\:=\:2}$

$\displaystyle{\bullet\:\sf\:b_2\:=\:-\:3}$

$\displaystyle{\bullet\:\sf\:c_2\:=\:-\:3}$

Now, we know that,

$\displaystyle{\pink{\sf\:D\:=\:\left|\begin{array}{cc}\sf\:a_1 & \sf\:b_1\\\sf\:a_2 & \sf\:b_2\:\end{array}\:\right|}}$

$\displaystyle{\implies\sf\:D\:=\:\left|\begin{array}{cc}\sf\:2 & \sf\:1\\\sf\:2 & \sf\:-\:3\:\end{array}\:\right|}$

$\displaystyle{\implies\sf\:D\:=\:2\:\times\:(\:-\:3\:)\:-\:1\:\times\:2}$

$\displaystyle{\implies\sf\:D\:=\:-\:6\:-\:2}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:D\:=\:-\:8}}}}$

∴ The value of D for the given simultaneous equations is - 8.

Answer 2

Answer:

Answer: Answer is D*= -8

Answer: Answer is D*= -8 this is right answer