for equiiteral triangle each of whose side is a length of any altitude of that triangle is
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If you draw a line from the top of the triangle that is perpendicular to the base you have created two identical right angle triangles. Using Pythagorean theory the square of the hypotenuse minus the square of the base equals the square of the other side (altitude). So 8*8=64, 4*4=16, 64–16=48 so the altitude of the triangle is the √48. I'm going to leave you work it out. Good luck!
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