Question

for equilibrium butane to iso butane if the value of kc is 3 the percentage by mass of isi butane in the equilibrium mixture would be​

Answer 1

Kc=3

Kc=|isobutane|/| butane|

3|butane|=|isobutane|

this shows butane is three times of isobutane....

so,if mixture contain xg isobutane then it contain 3xg butane

percentage of isobutane=x/4x ×100=25 percent..

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