Question

For every natural number ‘n’, 6n always ends with the digit
A. 0
B. 6
C. 4
D. 8 ​

Answer 1

Answer:

option b is correct

i.e. 6

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Answer 2

Answer:

0

Step-by-step explanation:

(2×3)^n=2^n×3^n

Therefore,it is not of the form of prime factorization 2^m×5^n

therefore 6^n can end with digit zero.