For every natural number n 6n always ends with whih digit
Answers
Answered by
1
Answer:
6n
(2×3)^n=2^n×3^n
Therefore,it is not of the form of prime factorization 2^m×5^n
therefore 6^n can never end with digit zero.
Thanks.
Answered by
0
Answer:
istiak sah it dh ish ish ish
Similar questions