Math, asked by amitmassey440, 10 months ago

For every natural number n 6n always ends with whih digit

Answers

Answered by gaurav1937
1

Answer:

6n

(2×3)^n=2^n×3^n

Therefore,it is not of the form of prime factorization 2^m×5^n

therefore 6^n can never end with digit zero.

Thanks.

Answered by shreyashkaregaonkar
0

Answer:

istiak sah it dh ish ish ish

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