Question

For f(x)=3x+1 and and g(x)=x^2-6, find (f*g)(x)

Answer 1

hey mate!!
u r given two functions..
f (x) = 3x+1
g (x) = x^2-6....

now we need to find f°g (x) = f {g (x)}
so put the value of g (x) in place of x of the function f (x)...
we get
value = 3 [x^2-6] +1
= 3x^2 -18 +1
= 3x^2 -17 ......ANS..

Answer 2

Answer:

The answer is

$(f*g)(x)=3x^3+x^2-18x-6$

Step-by-step explanation:

Given two functions

$f(x)=3x+1\text{ and }g(x)=x^2-6$

we have to find the value of (f*g)(x)

As the product of two functions can be expressed as

$(f*g)(x)=f(g)\times g(x)$

$f(x)=3x+1\text{ and }g(x)=x^2-6$

$(f*g)(x)=(3x+1)(x^2-6)$

$(f*g)(x)=3x(x^2-6)+1(x^2-6)$

$(f*g)(x)=3x^3-18x+x^2-6$

$(f*g)(x)=3x^3+x^2-18x-6$