For finding modulus of a complex number , can we use the formula r=root(x^2+y^2) instead of r(cosA + sin A) = z . In the examination? Will marks be deducted?
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Actually, complex number is expressed in cartesian form as well as polar form.
Cartesian form, z = x + iy
Polar form , z = r (cosA + sin A)
And modulus will be,
IzI = √(x²+y²)
or IzI = √[(rcosA)² + (rsinA)²]
= r²
Cartesian form, z = x + iy
Polar form , z = r (cosA + sin A)
And modulus will be,
IzI = √(x²+y²)
or IzI = √[(rcosA)² + (rsinA)²]
= r²
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