Question

For finding out Dry volume of stone work take ______more of wet volume *​

Answer 1

Answer:

Cement Concrete work

Assume wet volume of concrete = 10 cu.m

∴ Dry volume of concrete = 52% more of wet volume (50% to 55%)

∴ Dry volume of concrete = [(52/100) x 10] + 10 = 15.2 cu.m

Plastering (thickness 12mm)

Assume plastering area = 10 sq.m

∴ Wet volume of mortar = 10 x (12/1000) = 0.12 cu.m

Add 30% mortar to fill up the joints = [(30/100) x 0.12] + 0.12 =0.156 cu.m

∴ Dry volume 25% more = [(25/100) x 0.156] + 0.156 =0.195 cu.m

Pointing

Assume pointing area = 100 sq.m

∴ Volume of dry mortar = 0.7 cu.m per 100 sq.m

Flooring(2.5 cm thick)

Flooring with cement mortar or lime mortar

Assume flooring area = 100 sq.m

∴ Volume of wet concrete = 100 x (2.5/100) = 2.5 cu.m

Add 10% for unevenness = [(10/100) x 2.5] + 2.5 = 2.75 cu.m

Damp Proof Course (25 mm thick)

Assume area of D.P.C = 100 sq.m

∴ Volume of wet concrete = 100 x (25/1000) = 2.5 cu.m

Dry vulume of concrete = 52% more of wet volume = [(52/100) x 2.5] + 2.5 = 3.8 cu.m

Mosaic Tiles Flooring (20mm thick mortar)

Assume area of flooring = 100 sq.m

∴ Wet volume of mortar = 100 x (20/1000) = 2 cu.m

∴ Dry volume of mortar = 25% more of wet volume = [(25/100) x 2] + 2 = 2.5 cu.m

Brick masonry

Assume volume of brick masonry = 10 cu.m

∴ Dry volume of mortar = 35% of volume of masonry = (35/100) x 10 = 3.5 cu.m (allowing for wastage , frog filling etc.)

U.C.R masonry 

Assume of volume of masonry = 10 cu.m

∴ Dry volume of mortar = 42% of volume of masonry = (42/100) x 10 = 4.2 cu.m

Volume of stone = 1.25 x volume of masonry

Ashlar masonry

Assume volume of masonry = 10 cu.m

∴ Dry volume of mortar = 25% of volume of masonry = (25/100) x 10 = 2.5 cu.m

Volume of stone = 1.25 x volume of masonry

Coursed rubble masonry

Assume volume of masonry = 10 cu.m∴ Dry volume of mortar = 40% volume of masonry =(40/100) x 10 = 4 cu.mVolume of stone = 1.17 x volume of masonry