Question

For fixation of 6 molecules of CO2 and
formation of one molecule of glucose in
Calvin cycle, requires
a. 3 ATP and 2 NADPH,
b. 18 ATP and 12 NADPH,
c. 30 ATP and 18 NADPH,
d. 6 ATP and 6 NADPH,​

Answer 1

Answer:

b is correct answer

Explanation:

For fixation of 1 CO2,

ATP required - 3

NADPH required - 2

So, for fixation of 6 molecules of CO2, multiply each by 6

Net ATP = 18

Net NADPH = 12