Question

for general quadratic equation
$ax^{2} + bx + c = 0$
then find the value of
$\alpha + \beta$
​

Answer 1

Answer:

-b/a

Step-by-step explanation:

The general form of a quadratic equation in terms of it's zeros is:

p(x) = kx² - k(α + β)x + k(αβ), where k is a constant.

In the given equation,

a = k, b = -k(α + β), c = kαβ

Equating the value of b,

b = -k(α + β)

⇒ (α + β) = -b/k = -b/a   (∵ k = a)

Hence, the answer is -b/a

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