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Answered by
37
A + B + C = 180 degrees
implies A = 180 – ( B + C )
cos A = cos B cos C
b)
cos (180 – B – C) = cos B cos C
– cos ( B + C ) = cos B cos C
– cos B cos C + sin B sin C = cos B cos C
2 cos B cos C = sin B sin C
Hence tan B tan C = 2
a)
tanB+tanC=sinB/cosB+sinC/cosC
=(sinBcosC+sinCcosB)/cosBcosC
=sin(B+C)/cosA (cosA=cosB cosC)
=sin(180-B-C)/cosA
=sinA/cosA
=tanA
hope this helps you
implies A = 180 – ( B + C )
cos A = cos B cos C
b)
cos (180 – B – C) = cos B cos C
– cos ( B + C ) = cos B cos C
– cos B cos C + sin B sin C = cos B cos C
2 cos B cos C = sin B sin C
Hence tan B tan C = 2
a)
tanB+tanC=sinB/cosB+sinC/cosC
=(sinBcosC+sinCcosB)/cosBcosC
=sin(B+C)/cosA (cosA=cosB cosC)
=sin(180-B-C)/cosA
=sinA/cosA
=tanA
hope this helps you
Answered by
18
Answer:
=tanA
Step-by-step explanation:
A + B + C = 180 degrees
implies A = 180 – ( B + C )
cos A = cos B cos C
A) tanB+tanC=sinB/cosB+sinC/cosC
=(sinBcosC+sinCcosB)/cosBcosC
=sin(B+C)/cosA (cosA=cosB cosC)
=sin(180-B-C)/cosA
=sinA/cosA
=tanA
B) cos (180 – B – C) = cos B cos C
– cos ( B + C ) = cos B cos C
– cos B cos C + sin B sin C = cos B cos C
2 cos B cos C = sin B sin C
Hence tan B tan C = 2
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