Question

for given positive ion in cyclotron, obtain an expression for the cyclotron frequency???​

Answer 1

In cyclotron centripetal force is provided by magnetic force thus

mrw^2 = Bqv

mrw^2 = Bqrw. ..........(v = rw)

Therefore ,

mw = Bq implies w = Bq/m

As , w = 2πf

2πf = Bq/ m

And finally ,

f = Bq/ 2πm

This is the required equation.

May it help you

Answer 2

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$<b>$ Cyclotron

 

Cyclotron is a device used to accelerate charged particles to high energies. It was devised by Lawrence.

 

Principle

 

Cyclotron works on the principle that a charged particle moving normal to a magnetic field experiences magnetic lorentz force due to which the particle moves in a circular path.

 

Construction


It consists of a hollow metal cylinder divided into two sections D1 and D2 called Dees, enclosed in an evacuated chamber (Fig 3.21). The Dees are kept separated and a source of ions is placed at the centre in the gap between the Dees. They are placed between the pole pieces of a strong electromagnet. The magnetic field acts perpendicular to the plane of the Dees. The Dees are connected to a high frequency oscillator.
(Please see attached file 1)

 

Working:

When a positive ion of charge q and mass m is emitted from the source, it is accelerated towards the Dee having a negative potential at that instant of time. Due to the normal magnetic field, the ion experiences magnetic lorentz force and moves in a circular path. By the time the ion arrives at the gap between the Dees, the polarity of the Dees gets reversed. Hence the particle is once again accelerated and moves into the other Dee with a greater velocity along a circle of greater radius. Thus the particle moves in a spiral path of increasing radius and when it comes near the edge, it is taken out with the help of a deflector plate (D.P). The particle with high energy is now allowed to hit the target T.

  

When the particle moves along a circle of radius r with a velocity v, the magnetic Lorentz force provides the necessary centripetal force.

 

Bqv = (vm^2 ) / r

 v /r = Bq / m = constant ...(1)

 The time taken to describe a semi-circle

t = π r / v               (2)

 Substituting equation (1) in (2),

 t = π m/ Bq                   .. (3)

 It is clear from equation (3) that the time taken by the ion to describe a semi-circle is independent of

 (i) the radius (r) of the path and (ii) the velocity (v) of the particle

Hence, period of rotation T = 2t 

 T = 2 π m / Bq = constant ...(4)

 So, in a uniform magnetic field, the ion traverses all the circles in exactly the same time. The frequency of rotation of the particle,

v = 1 /T = Bq / 2 πm       .. (5)

If the high frequency oscillator is adjusted to produce oscillations of frequency as given in equation (5), resonance occurs.

Cyclotron is used to accelerate protons, deutrons and α - particles(now see attached file 2)


Limitations

 

a.     Maintaining a uniform magnetic field over a large area of the Dees is difficult.

 

b.     At high velocities, relativistic variation of mass of the particle upsets the resonance condition.

 

c.      At high frequencies, relativistic variation of mass of the electron is appreciable and hence electrons cannot be accelerated by cyclotron.



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