Question

For going to a city B from city A, there is route via city C such that AC I CB,
directly connects the two cities A and B. Find how much distance will be saved in
AC = 2x km and CB = 2(x + 7) km. It is proposed to construct a 26 km highway which
reaching city B from city A after the construction of highway.​

Answer 1

Answer:

Given, AC ⊥ CB, km,CB = 2(x + 7) km and AB = 26 km

On drawing the figure, we get the right angled ΔACB right angled at C.

Now, In ΔACB, by Pythagoras theorem,

Hence, the required saved distance is 34 – 26 i.e., 8 km.