Question

for GP a=7, r=1/3 find t6

Answer 1

t6=a(r)^6-1
t6=ar^5
t6=7(1/3)^5
t6=7(1/243)
t6=7/243 is answer

Answer 2

Given:

For an GP, a = 7

r = $\frac{1}{3}$

To find:

The value of $t_6$

Solution:

We can find the value by $t_6$ by using the following formula,

$t_n = a(r)^{n-1}$

a is the first term and r is the common ratio.

a = 7

r = $\frac{1}{3}$

n = 6

$t_6 = 7 (\frac{1}{3} )^{6-1}$

$t_6 = 7 (\frac{1}{3} )^{5}$

$t_6 = 7(\frac{1}{243})$

$t_6 =\frac{7}{243}$

Final answer:

The value of $t_6$ is $\frac{7}{243}$