For H2 + I2==2HI, at equilibrium some l2 is added to the reaction mixture at the
equilibrium.
a) is shifted to the right
b) gets shifted to the left,
c) remains unchanged
d) None of the above
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Answer:
Option (a) is shifted to the right.
Explanation:
- A reaction is said to be in equilibrium when the reaction quotient (Q) becomes equal to the equilibrium constant (K).
- So when this state gets subjected to any disturbance or stress i.e change in concentration, the position of equilibrium shifts.
- So this affects the concentration of both reactants and products. To regain the state of equilibrium, the system will tend to shift either towards the product side or towards the reactant side to attain the same value of K and Q. This process is well described by the famous 'Le Chatelier's Principle.
- In the reversible reaction, H₂+I₂ ⇄ 2HI, it tends to remain unchanged or balanced.
- At the equilibrium state, the addition of some I₂ the equilibrium balance gets disturbed due to the addition of some amount of reactant which affects equilibrium in the product.
- So to compensate for this, the reaction will move in a forwarding direction leading to the formation of more amount of products.
- So when the concentration of any reactant is added to the reactant side, it favors the reaction to proceed in a forward direction i.e. the equilibrium is shifted to the right.
Hence equilibrium (a) is shifted to the right.
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