For higher education, Trusha borrows Rs.9600 from the post-office for 2*1/2 years at the rate of 9%. How much interest and amount would she pay back at the end of the term?
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Given, P = Rs. 9600
T = 2 1/2 years = 5/2 years
r = 9 % /annum
we know, S.I = P × r × T/100
S.I = 9600 × 9 × 5/2/100
S.I = 48 × 45 = 2160
hence, interest = Rs. 2160
Rs. (2160 + 9600) = Rs. 11,760 she would pay back at the end of term.
T = 2 1/2 years = 5/2 years
r = 9 % /annum
we know, S.I = P × r × T/100
S.I = 9600 × 9 × 5/2/100
S.I = 48 × 45 = 2160
hence, interest = Rs. 2160
Rs. (2160 + 9600) = Rs. 11,760 she would pay back at the end of term.
Answered by
4
Given,
Principal (P)= ₹ 9600
Time (T) = 2 ½ years = 5/2 years
Rate of interest(R )= 9%
Interest on ₹ 100 for 1 year = ₹ 9
Interest on ₹ 9600 for 5/2 years (S.I)= P×R×T/100
[Simple Interest (S.I) = (P×R×T) /100]
S.I = 9600 × 9 × 5/2/100
S.I = 48 × 45
S.I = ₹ 2160
AMOUNT = PRINCIPAL +SIMPLE INTEREST
Amount = 9600 + 2160 = ₹ 11,760
Hence, Trusha would pay back ₹ 11,760 at the end of term.
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