Question

for how long tine period should a flow of 10^19 electrons be maintained between two points A and Bto have a constant current of 8A between them​

Answer 1

1A = 6.2 × 10^18 (in one second )

8A = 8 × 6.2 × 10^18 = 49.6 × 10^18

So as per the question we need to find the amount of time = 49.6 × 10^18 ÷ 6.2 × 10^18

= 8 second