Question

for how many distinct natural numbers K, √k + √(k+1) < 19 is possible
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Answer 1

Answer:

Step-by-step explanation:

$\sqrt{k} + \sqrt{k} + 1 < 19 \\ 2 \sqrt{k} + 1 < 19 \\ 2 \sqrt{k} < 19 - 1 \\ 2 \sqrt{k} < 18 \\ \sqrt{k} < 18 \div 2 \\ \sqrt{k} < 9 \\ k < 9 {}^{2} \\ k < 81$

80 distinct Natural Numbers are possible for this equation

hope it helps