For how many integers n will the inequality (n-5)(n-10)-3(n-2)<=0 be satisfied?
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Answered by
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we can write them separately as
n-5<=0
n<=5
n-10<=0
n<=10
-3(n)-2<=0
n=2/3
hence three numbers will satisfy the given inequality
2/3, , 5 and 10
Answered by
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Answer:
(n-5)(n-10)-3(n-2)<=0
n²-15n+50-3n+6<=0
n²-18n+56<=0
(n-14)(n-4)<=0
4<=n<=14
n={4,5,6,7,8,9,10,11,12,13,14}
Therefore,total numbers=11
Step-by-step explanation:
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