For how many natural numbers a is the expression
also a natural number?
Answers
Answered by
3
Answer:
Thus, n2−1 is an odd number dividing 64, i.e. n2−1=±1. The only solution there is n=0,a=−64 - but this is not a natural number.
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Answered by
1
Answer:
Answer: Only possible value of a is 1 .
Step-by-step explanation:
\sqrt{a + 64 / a- 64 }
a+64/a−64
By Bodmas rule , we have :-
=> \sqrt{a + \frac{64}{a} - 64 }
a+
a
64
−64
=> \sqrt{\frac{a^2 + 64 - 64a}{a} }
a
a
2
+64−64a
Since the expression is a rational number , then the expression \frac{a^2+64 - 64a}{a}
a
a
2
+64−64a
must be a perfect square .
Suppose \frac{a^2 + 64 - 64a}{a} = k^2
a
a
2
+64−64a
=k
2
for some k .
Then a² - 64a + 64 = ak²
Notice that by using a bit of logic , the RHS side is divisible by a , so the LHS side must also be divisible by a .
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