For how many number of electrons of Rb(Z=37)n+l = 5?
Answers
Answered by
1
Answer:
E.C of Rubidium is (Z=37) = 1s
22s
22p
6 3s
23p
64s
2 3d
104p
65s
The valence electron is in 5s orbital.
Its 4 quantum numbers are- n=5,l=0,m=0,s=+ 21
Explanation:
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Answered by
9
Explanation:
E.C of Rubidium is (Z=37) = 1s
2
2s
2
2p
6
3s
2
3p
6
4s
2
3d
10
4p
6
5s
1
The valence electron is in 5s orbital.
Its 4 quantum numbers are- n=5,l=0,m=0,s=+
2
1
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