Question

For how many number of electrons of Rb(Z=37)n+l = 5?​

Answer 1

Answer:

E.C of Rubidium is (Z=37) = 1s

22s

22p

6 3s

23p

64s

2 3d

104p

65s

The valence electron is in 5s orbital.

Its 4 quantum numbers are- n=5,l=0,m=0,s=+ 21

Explanation:

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Answer 2

Explanation:

E.C of Rubidium is (Z=37) = 1s

2

2s

2

2p

6

3s

2

3p

6

4s

2

3d

10

4p

6

5s

1

The valence electron is in 5s orbital.

Its 4 quantum numbers are- n=5,l=0,m=0,s=+

2

1

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