Math, asked by 24DP1195, 9 months ago

For how many positive integer values of k does kx^2+10x+k=0 have rational solutions?

Answers

Answered by ssweaney11
0

Answer:

3 by 3

Step-by-step explanation:

Answered by anandkumar4549
0

Answer: there are only two positive values of k for which the roots of given equation are rational

K = 3 and 4

Step-by-step explanation:

Condition for roots to be rational is that discriminant should be PERFECT SQUARE

So, D^2 = b^2 - 4ac

D^2 = 100 - 4k^2

Which is perfect square for

K = +3 , -3 , +4 & -4

But in question its positive

So, K = 3 & 4

Thank you!

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