For how many positive integer values of k does kx^2+10x+k=0 have rational solutions?
Answers
Answered by
0
Answer:
3 by 3
Step-by-step explanation:
Answered by
0
Answer: there are only two positive values of k for which the roots of given equation are rational
K = 3 and 4
Step-by-step explanation:
Condition for roots to be rational is that discriminant should be PERFECT SQUARE
So, D^2 = b^2 - 4ac
D^2 = 100 - 4k^2
Which is perfect square for
K = +3 , -3 , +4 & -4
But in question its positive
So, K = 3 & 4
Thank you!
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