for how many positive integer values of 'n'are both n/3and 3n three digit whole number is
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Minimum 4 digit number is 10001000
Maximum 4 digit number is 99999999
max=3n=9999max=3n=9999
nmax=3333nmax=3333
min=n3=1000min=n3=1000
nmin=3000nmin=3000
Keep in mind that n must be divisible by 3. So, the answer would be:
3333−30003+1=112
I hope it help you....
Maximum 4 digit number is 99999999
max=3n=9999max=3n=9999
nmax=3333nmax=3333
min=n3=1000min=n3=1000
nmin=3000nmin=3000
Keep in mind that n must be divisible by 3. So, the answer would be:
3333−30003+1=112
I hope it help you....
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