Question

for how many positive integer values of 'n'are both n/3and 3n three digit whole number is

Answer 1

Minimum 4 digit number is 10001000

Maximum 4 digit number is 99999999

max=3n=9999max=3n=9999

nmax=3333nmax=3333

min=n3=1000min=n3=1000

nmin=3000nmin=3000

Keep in mind that n must be divisible by 3. So, the answer would be:

3333−30003+1=112


I hope it help you....