Question

For how time a force 10 N must have acted on a body of mass 25 kg to bring it to rest from a velocity of 2 ms​

Answer 1

Answer:

5 second

Explanation:

F. = m× a

10. =. 25 × a

a. = 2/5 m/s ²

Now as we are stopping the body it is retardation so take a = -2/5 v=0 as rest and u = 2m/s

use v= u + at you will get it as 5 sec

Hope this helps you!!

Answer 2

Answer:

5 seconds

Explanation:

initial velocity = 2m/s

final velocity = 0m/s

force =10N

mass = 25kg

force = mass × acceleration

10N = 25 ×a

a = 10/25

a = 0.4 m/s^2

v = u+ at

0 = 2 + 0.4t

t= 5

time = 5 seconds