Question

For hydrogen atom, potential energy of the electron in first excited state is

Answer 1

Answer:

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Explanation:

If potential energy of an electron in a hydrogen atom in first excited state is taken to be zero, kinetic energy (in eV) of an electron in ground state will be. For this to be zero, We must add 6.8 eV.

Answer 2

The potential energy of electron in the first excited state of hydrogen atom is equal to -6.8 eV.

• The first excited state correspond to an orbit n=2.
• Total energy in nth orbit of hydrogen atom is equal to (-13.6/n²) eV.
• Total energy of first excited state (n=2) will be -3.4 eV.
• T.E=K.E + P.E ;  T.E=-K.E ⇒ P.E = 2×T.E
• So, the potential energy of the first excited state is equal to -6.8 eV.