Question

For hydrogen atom the energy of photon emitted during a transition from n=2 state to n= 1 state is

Answer 1

Explanation:

$e = 2.18 \times {10}^{ - 18} ( \frac{1}{n {1}^{2} } - \frac{1}{ {n2}^{2} } ) \\ = 2.18 \times {10}^{ - 18} ( \frac{1}{{1}^{2} } - \frac{1}{ {2}^{2} } ) \\ = 2.18 \times {10}^{ - 18} ( \frac{3}{4} ) \\ = \frac{6.54\times \: {10}^{ - 18} }{4} \\ = 1.635 \times {10}^{ - 18} j$